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Homework 3 Solutions, Electromagnetic Theory II.pdf

For ω = ω0/2: vg= 3 19 √5c≈0.35c vp=c√ 1 5 ≈0.45c In a region of low, normal dispersion, both velocities are the below the speed of light and about the ...  Down

Jackson 10.4 Homework Problem Solution - Faculty Server.pdf

2ϵ* ⋅p∣2 d σ dΩ = (ϵr ...  Down

Physics 7602 SPRING 2014 Problem Set S6 Due Tuesday.pdf

~2 √ ~2 2mϵ = L π √ 2m ~2 ϵ (5) Note that there is an additional factor of two since for every ...   Down

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